$a\frac{5}{4}b\frac{13}{4}$
$\int9x^2\left(x^3+1\right)^2dx$
$\int ( x ^ { 3 } - 5 x ) ^ { 5 } ( 3 x ^ { 2 } - 5 ) d x$
$\left(2x^2-5x+6\right)\cdot\left(3x^4-5x^3-6x^2-4x-3\right)$
$\left(12a-15b+3c\right)+\left(8a+6b-3c\right)$
$\frac{2x^3-5x^2+6x-3}{x+2}$
$\int\frac{x}{4\cdot\sqrt{1+4x^2}}$
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