$3\left(x+5\right)+7\:>\:5\left(x+2\right)$
$\sqrt[4]{x^3}=\frac{1}{x^{-1}}$
$49w^2-36u^2$
$-74\cdot4$
$-8ab+2ab$
$\left(a\:+\:4\right)\:\left(a\:-\:2\right)\:$
$4-3y-y^2$
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