$\int\frac{x-4}{9x^3-12x^2+4x}dx$
$z^2-4z-12$
$2x^3-2x^2+4x-4$
$\left(x^2\right)^y\cdot\left(x^3\right)^{-y}\cdot\left(4^{y^2}\right)^{y^{-2}}$
$5x^{4}x+3y+5x^{4}+3$
$\left(2.23606797749979+1.4142135623730951\right)^2-2\left(\sqrt{10}-4\right)$
$\left(\:x^4-x^3\:+4\right)-\left(3x^2-5x+5\right)$
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