$\frac{2x-3}{x-2}<-2$
$8x^2-4x-5=0$
$cos\:2x=1\:+\:4\:sen\:x$
$4\:-\:8\:-\:\left(-16\right)$
$\frac{5xy^2}{2}\cdot\:\sqrt{6}$
$\cos\:\left(x\right)\cot\:\left(x\right)=-\cos\:\left(x\right)$
$csc^4\theta\:-cot^4\theta\:=2csc^2\theta\:-1$
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