$x^4-4$
$e^{-2x}\frac{dy}{dx}=\frac{y}{4y-3}$
$\left(\:-\:2\:\right)\left(\:2\:\right)\left(\:5\:\right)\left(\:-\:5\:\right)$
$48\cdot16$
$\int\left(3x\right)\left(6-x^2\right)dx$
$100a^{10}\:-\:60a^5b^4+\:9b^8$
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