$\frac{3x^3-2x^2+6x-4}{x-5}$
$x^2+3x-2;\:x=3$
$-15\cdot56$
$\int\left(x^2+2\right)^2\:3x^2\:dx$
$\frac{1+\tan^2\left(x\right)}{\tan\left(x\right)\cdot\sin\left(x\right)}=\csc\left(x\right)$
$\frac{3y}{4}+\frac{y}{2}-\frac{y}{3}$
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