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Exercise

$-ke^{-kt}\:-2\pi f\:\sin\left(2\pi ft\right)$

Step-by-step Solution

1

Factor the polynomial $-ke^{-kt}+2\cdot -\pi f\sin\left(2\pi ft\right)$ by it's greatest common factor (GCF): $-1$

$-\left(ke^{-kt}+2\pi f\sin\left(2\pi ft\right)\right)$

Final answer to the exercise

$-\left(ke^{-kt}+2\pi f\sin\left(2\pi ft\right)\right)$

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