$2^3\:+\:-4^3$
$10+6y=16$
$\frac{\sin\left(x\right)^2}{\cos\left(x\right)^2}+1=\sec\left(x\right)^2$
$\left(3a^2-5b+c\right):4ac$
$( m + 2 ) ^ { 3 } ( m - 2 ) ^ { 3 }$
$\left(5x+3\right)\left(10x+4\right)$
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