$4^x\left(2^{x-2}\right)=128$
$197^2$
$2\left(\frac{1}{2}a\right)\left(\frac{2}{3}b\right)$
$\left(9x^9\:-\:10b^6\right)\:\left(9^9\:+\:10b^6\right)$
$\left(x+1\right)^2-\left(x+2\right)^2$
$\left(9x-x^3\right)\left(3x+5\right)$
$2x+1\:+\:2x-1$
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