$\lim_{x\to0}\left(\frac{1}{x+1}x^2\right)$
$\left(2x-3y-z^2\right)\left(x+y-2z^2\right)$
$100r^2-160r+64$
$\:7x+8y-x+3y$
$9b+8+2\left(12b-8\right)$
$f\left(x\right)=\frac{x^{2}\left(x-9\right)^{3}}{\left(x^{2}+9\right)^{2}}$
$\left(2x+1\right)\left(2x+7\right)$
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