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Exercise

$1+\cot^2\left(\frac{2\pi}{3}\right)$

Step-by-step Solution

1

Apply the trigonometric identity: $1+\cot\left(\theta \right)^2$$=\csc\left(\theta \right)^2$, where $x=\frac{2\pi }{3}$

$\csc\left(\frac{2\pi }{3}\right)^2$
Why is cot(x)^2+1 = csc(x)^2 ?

Final answer to the exercise

$\csc\left(\frac{2\pi }{3}\right)^2$

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