Exercise
$1+cos\left(2x\right)+sin^2\left(x\right)=1$
Step-by-step Solution
Learn how to solve integral calculus problems step by step online. Solve the trigonometric equation 1+cos(2x)sin(x)^2=1. Applying an identity of double-angle cosine: \cos\left(2\theta\right)=1-2\sin\left(\theta\right)^2. Combining like terms -2\sin\left(x\right)^2 and \sin\left(x\right)^2. We need to isolate the dependent variable x, we can do that by simultaneously subtracting 2 from both sides of the equation. Subtract the values 1 and -2.
Solve the trigonometric equation 1+cos(2x)sin(x)^2=1
Final answer to the exercise
$x=\frac{1}{2}\pi+2\pi n\:,\:\:n\in\Z$