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Exercise

$1\left(-a+b\right)\left(-a+b\right)-1$

Step-by-step Solution

1

Any expression multiplied by $1$ is equal to itself

$\left(-a+b\right)\cdot \left(-a+b\right)-1$
2

When multiplying two powers that have the same base ($-a+b$), you can add the exponents

$\left(-a+b\right)^2-1$
3

A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: $(a-b)^2=a^2-2ab+b^2$

$a^2-2ab+b^2-1$

Final answer to the exercise

$a^2-2ab+b^2-1$

Try other ways to solve this exercise

  • Choose an option
  • Product of Binomials with Common Term
  • FOIL Method
  • Find the integral
  • Find the derivative
  • Factor
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
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Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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