$\left(3x^2+4\right)\left(3x-4\right)$
$-z+y-3z=-1$
$\int ( x + 5 ) ^ { 2 } d x$
$f\left(x\right)=\frac{x^2-25}{6x^3-24x^2-30x}$
$\frac{4}{x^2-8x+12}=\frac{x}{x-2}+\frac{1}{x-6}$
$\lim_{x\to3}\left(x+5\right)$
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