$-4+6-2+5-\left(-3\right)$
$\frac{1}{3^{\infty}}$
$\int12x^2e^{4x^3-5}dx$
$-x^2-10x-8=0$
$\frac{3x^3-27}{x-3}$
$\left(-10\right)^0\cdot\frac{1}{3^{-3}}$
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