$6e^{3x-1}-y=z$
$\frac{2\cos\left(x\right)}{1-\sin^2\left(x\right)}$
$y\frac{x^2}{e^{2x}}$
$\int ln\left(x^3\right).\:\frac{x^4}{4}-\int\:\frac{x^4}{4}.\:\frac{2}{x}dx$
$16b^2-1\:=\:0$
$12x^{2}+15y^{3}-24z^{5}$
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