$-3x+yx$
$16x^2-40x=11$
$\int_{-3}^2\left(\frac{1}{\left(x+2\right)^{\frac{4}{3}}}\right)dx$
$\:\int_{58}^{100}\pi\left(\left(-.12\right)\left(y-100\right)\right)^2dy$
$10-1+2$
$\frac{8x^2-5x+24}{8x+2}$
$x^2\frac{dy}{dx}=\sqrt{y}\left(5x+1\right)$
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