$\int5sec\left(\frac{x}{2}\right)^2dx$
$-10+1+2$
$\int\:\:\frac{\left(e^{\frac{2}{5}m+4}\right)}{4}dm$
$-4-12-\left[\left(-13-20+8\right)-4\right]$
$\frac{2x+3}{\:4x-1}=\frac{3x-2}{3x+2}$
$5x^2=-35x$
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