$\left(m^2-4m+1\right)^2$
$f\left(x\right)=\:\frac{\left(3e^x-1\right)}{2-2e^x}$
$7b-b-x+5-2x-7b$
$\log732=2.8645$
$\lim_{x\to\infty}\left(ln6x-ln\left(x+4\right)\right)$
$5\cdot11$
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