$ln\:\left(3x+y\right)=0$
$12\sin^2\left(x\right)+7\cos\left(x\right)-13$
$3z+2\left(\left(-5z\right)\right)+6$
$\frac{-10y^4}{5y^3}$
$\frac{d}{dx}y^2-6y+9=12x-24$
$16u-5y+3u+7u$
$\frac{3a^2-2a+4}{3a^2-a}$
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