$3.\left(4+x\right)=5.\left(x+4\right)+1=3x$
$x\:y'\:=\:sqrt\left(x\:y\right)+y$
$\left(9a^2b-b^2\right)^3$
$12x^3+12x^2-6x$
$\sqrt[3]{\frac{x}{y}}$
$\lim_{x\to0}\frac{x^2-x-2}{x-2}$
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