$y^2-2y=3$
$\frac{20a^3c^4d^2}{-5x^3y^2}$
$\frac{a^2\left(4-9b^2\right)}{36}$
$-2\left(2x+3\right)-2\left(2y+2\right)$
$\frac{d}{dx}7x^3-8cxy+22y^2=0$
$x-7=2x+1$
$\left(7.86\:x\:10^{12}\right)\left(1.68\:x\:10^{-3}\right)$
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