$\int\:\:e^{2t}dx$
$\int\frac{sec\left(x\right)^2}{tan\left(x\right)^3-tan\left(x\right)}dx$
$\frac{2x^3-x^2-19x+15}{x-3}$
$ln\left(x-6\right)+ln\left(x+6\right)=0$
$5.6-\left(-3.4\right)$
$\int_{-1}^12^{3x}dx$
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