Simplify the trigonometric expression 2tan(b)cos(b)^2+1

 Exercise

$2\cdot\tan\left(b\right)\cdot\cos\left(b\right)^2\:+1$

 

Applying the tangent identity: $\displaystyle\tan\left(\theta\right)=\frac{\sin\left(\theta\right)}{\cos\left(\theta\right)}$

$\frac{2\sin\left(b\right)}{\cos\left(b\right)}\cos\left(b\right)^2+1$

 Why is tan(x) = sin(x)/cos(x) ?

 

Multiplying the fraction by $\cos\left(b\right)^2$

$\frac{2\sin\left(b\right)\cos\left(b\right)^2}{\cos\left(b\right)}+1$

 

Simplify the fraction $\frac{2\sin\left(b\right)\cos\left(b\right)^2}{\cos\left(b\right)}$ by $\cos\left(b\right)$

$2\sin\left(b\right)\cos\left(b\right)+1$

$2\sin\left(b\right)\cos\left(b\right)+1$

 Try other ways to solve this exercise

Can't find a method? Tell us so we can add it.