$\lim_{x\to0.5}\left(\frac{e^{-2x\:}-1}{x}\right)$
$\:18x+24$
$\lim_{t\to4}\left(\frac{t^3+64}{t+4}\right)$
$x^2+12x\:>6x$
$\left(n+3\right)\left(n-5\right)$
$275\cdot25$
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