$10^2+34x-3+5$

$\frac{\left(12x^5y^3-9x^2y+4x^3y^2\right)}{\left(6xy^2\right)}$

$-xy^2+9xy^2+4xy^2$

$\left(-2-2x\right)^2$

$\lim_{x\to\infty}\left(\frac{x^2+1}{x+1}\right)^{\frac{1}{x}}$

$\ln\left(4ex-3e\right)=\ln\left(x\right)+1$

$in\left(x+y\right)=\arctan\left(xy\right)$