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Exercise

$2\left(150.000+3x\right)+6x+20\left(x-2.000\right)$

Step-by-step Solution

1

Multiply the single term $2$ by each term of the polynomial $\left(150+3x\right)$

$300+6x+6x+20\left(x-2\right)$
2

Multiply the single term $20$ by each term of the polynomial $\left(x-2\right)$

$300+6x+6x+20x-40$
3

Add the values $300$ and $-40$

$260+6x+6x+20x$
4

Combining like terms $6x$ and $6x$

$260+12x+20x$
5

Combining like terms $12x$ and $20x$

$260+32x$

Final answer to the exercise

$260+32x$

Try other ways to solve this exercise

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  • Product of Binomials with Common Term
  • FOIL Method
  • Find the integral
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  • Integrate by substitution
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  • Integrate using tabular integration
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Similar Questions Solved

$\left(x+2\right)\left(x+3\right)$

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$\left(6x-5\right)\left(2x+3\right)$

$4\left(4a+5\right)$

$\left(5x+2y\right)\left(5x-2y\right)$

$\left(2x+6\right)^2$

$\left(x-6\right)\left(x-5\right)$

Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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