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Exercise

$2\left(f-9\right)+2\left(-3f+9\right)$

Step-by-step Solution

1

Multiply the single term $2$ by each term of the polynomial $\left(f-9\right)$

$2f-18+2\left(-3f+9\right)$
2

Multiply the single term $2$ by each term of the polynomial $\left(-3f+9\right)$

$2f-18-6f+18$
3

Add the values $-18$ and $18$

$2f+0-6f$
4

$x+0=x$, where $x$ is any expression

$2f-6f$
5

Combining like terms $2f$ and $-6f$

$-4f$

Final answer to the exercise

$-4f$

Try other ways to solve this exercise

  • Choose an option
  • Product of Binomials with Common Term
  • FOIL Method
  • Find the integral
  • Find the derivative
  • Factor
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
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Similar Questions Solved

$\left(x+2\right)\left(x+3\right)$

$\left(2+\sqrt{y}\right)\left(2-\sqrt{y}\right)$

$\left(6x-5\right)\left(2x+3\right)$

$4\left(4a+5\right)$

$\left(5x+2y\right)\left(5x-2y\right)$

$\left(2x+6\right)^2$

$\left(x-6\right)\left(x-5\right)$

Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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