k8+6=20\frac{k}{8}+6=208k+6=20
(2−2)3.2−4\left(2^{-2}\right)^3.2^{-4}(2−2)3.2−4
(2x+11)⋅(2x+11)\left(2x+11\right)\cdot\left(2x+11\right)(2x+11)⋅(2x+11)
−38−(1)-38-\left(1\right)−38−(1)
y−16−192y-16-192y−16−192
x+20<8x+20<8x+20<8
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