$\int\left(2x^2\left(4x^3+5\right)^4\right)dx$
$3\left(-2x+6\right)+10\left(5x-8\right)$
$\frac{320}{4}$
$\lim_{x\to2}\left(1-x^2\right)$
$4x^3\left(x+h\right)-5x^2\left(x+h\right)+7x+20$
$-2\left(-7p-10\right)$
$\int\left(x^2\left(x^3-4\right)^{18}\right)dx$
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