$\frac{4x^6-2x^4+5x^2}{x^2}$
$5x-10>0$
$\left(-17\right)-\left(-21\right)-\left(-8\right)+\left(-54\right)-\left(96\right)$
$\left(x^2+5y\right)^4$
$\frac{10^0}{10^{-12}}$
$\int5u^5\sqrt{u^6+8}du$
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