$\frac{x^2-5x-6}{x-6}$
$\frac{2x-5}{12}=\frac{-x}{4}-\frac{5}{3}$
$4\left(x-5\right)+27\le4x-9$
$\left(a+b\right)15\:6^{b+1}\:8^{a-4}$
$\left(t^2-xt^2\right)\frac{dx}{dt}+x^2+tx^2=0$
$\left(x^4+y^6\right)^5\:$
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