$-16+\left(12-1\right)\left(5-6\right)$
$8^x=1'$
$3\left(2x+1\right)\left(1+x+x^2\right)^2$
$12e^{0.012\cdot5}$
$\left(-24+-25\right)+\left(-50+-10\right)$
$\left(x^2-10\right)\left(x^2-3\right)$
$-10u=-27-7u$
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