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Exercise

$27\left(-\frac{2}{3}x\:+\:\frac{1}{3}\right)-\:5x$

Step-by-step Solution

1

Simplify the fraction $27\cdot \left(\frac{-\frac{2}{3}\cdot +1}{3}\right)$

$9\cdot \left(-\frac{2}{3}\right)\cdot +1-5x$
2

Multiply the fraction and term in $9\cdot \left(-\frac{2}{3}\right)\cdot +1$

$\frac{9\cdot -2}{3}\cdot +1-5x$
3

Multiply $9$ times $-2$

$-\frac{18}{3}\cdot +1-5x$
4

Divide $-18$ by $3$

$-6\cdot +1-5x$

Final answer to the exercise

$-6\cdot +1-5x$

Try other ways to solve this exercise

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Similar Questions Solved

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$9a-3a+5a$

$-x-x$

$-3x-9+15x$

$a+2a+9a$

Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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