$$\frac{4d^2}{2}+\frac{16n^2}{2}-1;\:m=6;\:n=\frac{1}{4}$$

$$2x^2+4x-126$$

$$\int\frac{12}{\left(3x+1\right)^5}dx$$

$$\left(3+\sqrt{a}\right)\left(3-\sqrt{a}\right)$$

$$f\left(x\right)\:=\:\left(x^2-4x+4\right)^4$$

$$\left(4+\frac{9}{n}\right)\left(4+\frac{9}{n}\right)$$