$\int_0^{15}\left(4t^2+3t\right)^2dx$

$\lim_{x\to-\infty}\left(\frac{\left|8x+6\right|}{4x-2}\right)$

$\left(1+t\right)\:\left(1-t\:+\:t^2\right)$

$\frac{sin\left(5x\right)}{sinx}-\frac{\cos\left(5x\right)}{cosx}=\frac{2sin4x}{sin2x}$

$\frac{\sqrt{x^2}-25}{x}$

$-3\left(-5\right)^2-12\left(-5\right)-12$