$y=\frac{x-5}{2x-4}$
$4\left(6\right)^2\left(7\right)$
$\left(y\cdot\ln\:\left(x\right)\right)^{-1}\cdot\frac{dy}{dx}=\left(\frac{x}{y+1}\right)^2$
$\frac{d^3}{dx^3}\left(3x^4-2x^2+1\right)$
$x^3-2x^2-3x=0$
$\frac{dx}{dt}+5x^2=25$
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