$+\frac{x+5}{x^2+x}$
$x^3-0x^2-8x-4$
$\lim_{x\to0}\left(\frac{3x\left(cos\left(4x-1\right)\right)}{sin\left(6x\right)-6}\right)$
$\frac{4}{49}\left(m^2\right)-\frac{32}{7}\left(mn\right)+64n^2$
$2\left(2x-8\right)-8x\le4$
$9a-4a$
$7m+m-5a+a^2$
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