Exercise
$2y^2-20y+32=0$
Step-by-step Solution
Learn how to solve one-variable linear inequalities problems step by step online. Solve the quadratic equation 2y^2-20y+32=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=2, b=-20 and c=32. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 20 and -12.
Solve the quadratic equation 2y^2-20y+32=0
Final answer to the exercise
$y=8,\:y=2$