$\frac{4}{3}+\frac{4}{3}+\frac{4}{3}$
$\left(-\:3.756\right)\cdot7$
$1-a^2=\left(1-a\right)\left(1+a\right)$
$\left(3p+2q^3\right)^5$
$\lim_{x\to\infty}\left(-3\right)$
$a-2\sqrt{a}\cdot\sqrt{2b}-2b$
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