$x^2+3>\:4x$
$\frac{\left(6y^3\right)^4}{2y^5}$
$\int\left(x^3\sqrt{x^2+43}\right)dx$
$4a+7b-2a+8-3b+9-2$
$-4=\csc\left(theta\right)$
$\left(x-4\right)\left(x+1\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!