$\frac{\left(10x-5\right)}{25^2-1}$
$\tan\left(x-40\right)=1.5$
$3u^2x+3u^2y-u^2vx-u^2vy$
$1+tan2\:a=\sec\left(x\right)$
$y^6\sqrt[3]{y}$
$\int\frac{\left(1+\ln\left(x\right)\right)}{x^3}dx$
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