Exercise
$3\left(cos\left(4x\right)\right)^2=9\left(sin\left(4x\right)\right)^2$
Step-by-step Solution
Learn how to solve problems step by step online. Solve the trigonometric equation 3cos(4x)^2=9sin(4x)^2. Simplify, dividing both sides of the equality by . Grouping all terms to the left side of the equation. Applying the trigonometric identity: \sin\left(\theta \right)^2 = 1-\cos\left(\theta \right)^2. Multiply the single term -3 by each term of the polynomial \left(1-\cos\left(4x\right)^2\right).
Solve the trigonometric equation 3cos(4x)^2=9sin(4x)^2
Final answer to the exercise
$x=\frac{1}{6}\pi+2\pi n,\:x=\frac{11}{6}\pi+2\pi n\:,\:\:n\in\Z$