Apply the formula: $a\log_{b}\left(x\right)$$=\log_{b}\left(x^a\right)$
Using the power rule of logarithms: $n\log_b(a)=\log_b(a^n)$
The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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