$8\left(4t+9\right)$
$\:4\left(x\:+\:1\right)\:+\:2\left(2x\:-\:3\right)\:$
$16^2+24xy+9y^2$
$\int_0^1\left(\frac{\cos\left(x\right)}{x}\right)dx$
$\lim_{x\to-4}\left(\frac{x-4}{x}\right)$
$\left(1+x\right)^{\frac{1}{2}}\frac{dy}{dx}=xy^3$
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