$-\left(-98\right)+\left(-1\right)$
$\int\frac{1}{\left(4+x\right)^2\left(4+2x\right)}dx$
$\frac{3}{2}x^4\frac{1}{2}x^405x^4$
$x^2-5x<-54$
$\sec^{2}\frac{x}{2}=\frac{2\sec x}{1+\sec x}$
$\int3\left(3x+12\right)^7dx$
$\left(5+0.1\right)\left(1-0.01\right)$
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