$\frac{dy}{dx}\left(\left(x^3+2y^2\:\right)^5\:=y\right)$
$\frac{80}{4}-\frac{60}{20}$
$\frac{1}{4}+cos^2\left(a\right)=1$
$\frac{-12\pm\sqrt{12^2-4\left(1\right)\left(24\right)}}{2\left(1\right)}$
$6y\frac{d}{dx}+2x^2=0$
$\frac{1}{\sec}=\sin^{2}\cdot\cos^{2}+\cos^{4}$
$\lim_{x\to0}\frac{senx\:-x}{cos\:x\:-1}$
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