Final answer to the problem
$3\left(x-\frac{2}{3}\right)^2+3\cdot \left(\frac{2}{3}-\frac{4}{9}\right)$
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Step-by-step Solution
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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
Use the complete the square method to factor the trinomial of the form $ax^2+bx+c$. Take common factor $a$ ($3$) to all terms
$3\left(x^2-\frac{4}{3}x+\frac{2}{3}\right)$
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$3\left(x^2-\frac{4}{3}x+\frac{2}{3}\right)$
Learn how to solve polynomial factorization problems step by step online. Factor the expression 3x^2-4x+2. Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (3) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial x^2+-\frac{4}{3}x+\frac{4}{9}. Multiply the fraction and term in - \frac{2}{3}.
Final answer to the problem
$3\left(x-\frac{2}{3}\right)^2+3\cdot \left(\frac{2}{3}-\frac{4}{9}\right)$
