$3x\left(x^2-5\right)$
$\int_0^3\left(\frac{x^3}{\left(x^2+9\right)^{0.5}}\right)dx$
$\left(-4x+10x^2-8\right)\left(\left(2x-1\right)\left(3x+2\right)\right)$
$x^8-256$
$-2009-209$
$5x-6x^3+8x$
$16x^3yz^2\:and\:24x^2yz^4$
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