$y+y'-4x^3y=0$
$\frac{m^6-4096n^6}{m+4n}$
$\frac{4}{3}xy-\frac{2}{9}x^2y+\frac{8}{9}xy^2$
$2x^8\cdot4x^3$
$\left(3g+2y\right)\left(3x-2y\right)$
$\int\:\frac{1}{2}s^{10}\:ds$
$x^2+z=9$
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